1. Rain Trainer
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Originally Posted by Josiah
Could you please explain this mechanic for my sleep deprived mind? I legitimately forgot what I was supposed to be doing.
8 cards got one of the two values. Of these, 7 comes before at least one other. The chance that there is zero cards between two specific of those cards is 1/13. The chance that there are other cards between those two specific cards is 12/13. The chance that there are other cards between all those 8 specific cards is therefore (12/13)^7 and the chance that at least two of them are next to each other is 1-(12/13)^7.

2. Originally Posted by Ludwig
Closer, but still wrong.
You will find a "first" correct card 8 times.
I was working under the assumption that no specific first card was being looked for.

3. Rain Trainer
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Originally Posted by PsychedelicJellyfish
I was working under the assumption that no specific first card was being looked for.
Neither was I.

4. Originally Posted by PikaPika677
If I had a standard deck of 52 playing card and shuffled it thoroughly, what are the chances of 2 cards of my choice (suits don't count. Only the value of the cards. Like 10 and 5 or Ace and King) appearing right next to each other when I look through the deck?
I actually think it is 1/13*(1/13+51/52)

the first card is definitely 1/13, however, the second card have the probability shifted since one of the number's repetition has been reduced from 4 to 3. but then i could be wrong lol.

5. I don't know if that was supposed to be sarcastic or not but it helped! Thanks.

6. Originally Posted by Josiah
I could be completely screwing this up, but I think it should be something like 1/13 x 1/13 which would come out to be that 1/169 times you try this it will work.

Seriously, careful on taking my word for it.
Originally Posted by PsychedelicJellyfish
I think it's actually 1 in 13. Because when you look through the deck, you will always find one of the cards at some point, because it's in the deck, so the probability of finding the first card doesn't matter. The probability that's relevant is the likelihood of the other card you want being next to the first card. There's four cards of each value in the deck, so the likelihood of whatever card you want being next to the first card is 1 in 13.

For example, you look through the deck and find a king. The chance of an ace being next to it is 1 in 13.

I hope that makes sense. I have a nasty feeling that it doesn't.
Originally Posted by Ludwig
8 cards got one of the two values. Of these, 7 comes before at least one other. The chance that there is zero cards between two specific of those cards is 1/13. The chance that there are other cards between those two specific cards is 12/13. The chance that there are other cards between all those 8 specific cards is therefore (12/13)^7 and the chance that at least two of them are next to each other is 1-(12/13)^7.
Originally Posted by Kacho
I actually think it is 1/13*(1/13+51/52)

the first card is definitely 1/13, however, the second card have the probability shifted since one of the number's repetition has been reduced from 4 to 3. but then i could be wrong lol.
Hmmm. I'll try to do this myself. Let's say I'm looking for a King and a Queen. There will always definitely be a King somewhere in the deck, but what are the chances of a Queen being next to one of the Kings? There are 4 Kings and 4 Queens. For the first King, there are 4 Queens vs. 44 other cards (because there are 52 cards total but I subtracted the 4 Kings and the 4 Queens). So you could have one of the 4 Queens next to the King or you could one of the other cards appear next to the King. So if I got got the 4 Queens and mixed them together with 44 cards then picked a card at random, I'd have a 1 in 11 chance of grabbing a Queen. So for the first King, there is a 1/11 chance for him to be next to a Queen.

But wait, there are 3 other Kings. All 4 Kings have a 1/11 (9.0909%) chance of being next to a Queen so even if one King is not beside a Queen, it is possible that another King is. The chances of one King not being next to a Queen is 90.9091% or .909091. So .909091^4 equals .683013. There is a 68.3013% chance that there will be no Kings next to Queens. Or you could just say there is a 31.6987% chance of at least one King appearing next to a Queen.

Did I do this right?

7. Originally Posted by TeamRocketGrunt
I don't know if that was supposed to be sarcastic or not but it helped! Thanks.
Not sarcastic at all!
Tvtrope is like a wikipedia of most things media and entertainment.
You see tropes you never thought existed in certain shows or anime.

Just don't get too distracted and forget to do homework.

I also use this site to pick up new shows.

8. Which is worse: parents who do the bare minimum for their children and then manipulate them into thinking they care so the child feels bad if they think otherwise, or parents who do the bare minimum (or nothing at all) for their children and then don't even pretend to care?

I hope that makes sense. Inspired by the time where I drove myself to the emergency room once when my entire body was in sudden extreme pain. I had to drive myself because my parents just kept arguing since neither one of them wanted to take me. Other, similar things have happened, yet they always tell me they care/love me and then ask why I don't like being around them much.

9. Originally Posted by diamondpearl876
Which is worse: parents who do the bare minimum for their children and then manipulate them into thinking they care so the child feels bad if they think otherwise, or parents who do the bare minimum (or nothing at all) for their children and then don't even pretend to care?

I hope that makes sense. Inspired by the time where I drove myself to the emergency room once when my entire body was in sudden extreme pain. I had to drive myself because my parents just kept arguing since neither one of them wanted to take me. Other, similar things have happened, yet they always tell me they care/love me and then ask why I don't like being around them much.
I'd say they are equally bad, but in their own way.

Manipulative is terrible, but so is not caring at all.

10. Originally Posted by G50
I'd say they are equally bad, but in their own way.

Manipulative is terrible, but so is not caring at all.
Fair enough. I guess each type brings about a different set of problems for the children.

11. Rain Trainer
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Originally Posted by Kacho
I actually think it is 1/13*(1/13+51/52)

the first card is definitely 1/13, however, the second card have the probability shifted since one of the number's repetition has been reduced from 4 to 3. but then i could be wrong lol.
It's wrong. You also remove non-correct cards when you progress though the deck, so it evens out.

Also, I don't see how you got those numbers from that information.
My solution is the correct one.

Originally Posted by PikaPika677
Hmmm. I'll try to do this myself. Let's say I'm looking for a King and a Queen. There will always definitely be a King somewhere in the deck, but what are the chances of a Queen being next to one of the Kings? There are 4 Kings and 4 Queens. For the first King, there are 4 Queens vs. 44 other cards (because there are 52 cards total but I subtracted the 4 Kings and the 4 Queens). So you could have one of the 4 Queens next to the King or you could one of the other cards appear next to the King. So if I got got the 4 Queens and mixed them together with 44 cards then picked a card at random, I'd have a 1 in 11 chance of grabbing a Queen. So for the first King, there is a 1/11 chance for him to be next to a Queen.

But wait, there are 3 other Kings. All 4 Kings have a 1/11 (9.0909%) chance of being next to a Queen so even if one King is not beside a Queen, it is possible that another King is. The chances of one King not being next to a Queen is 90.9091% or .909091. So .909091^4 equals .683013. There is a 68.3013% chance that there will be no Kings next to Queens. Or you could just say there is a 31.6987% chance of at least one King appearing next to a Queen.

Did I do this right?
No.
Read my solution and I'll explain further if you don't understand it.

12. So I happen to have a tumblr account that has gone unused sine I set it up a few weeks ago. I am thinking about becoming active on it.

My only question is what exactly is Tumblr for ?

It seems to be like a blog but with shorter posts, but I feel like I am missing something here. What exactly am I supposed to post on it ?

13. Originally Posted by Glass Eye
So I happen to have a tumblr account that has gone unused sine I set it up a few weeks ago. I am thinking about becoming active on it.

My only question is what exactly is Tumblr for ?

It seems to be like a blog but with shorter posts, but I feel like I am missing something here. What exactly am I supposed to post on it ?
You just post things and re-blog posts from other people. There's not much to it really though you can find some really cool pictures if you're interested in that kind of stuff.

14. I was looking forward to getting a Stormrunner T-shirt at Hershey Park the other day, but I didn't have enough money

Are those shirts sold on eBay

15. If you delete your trade shop, are you allowed to make another one [for the same gen]?

16. Originally Posted by Gelatino95
I was looking forward to getting a Stormrunner T-shirt at Hershey Park the other day, but I didn't have enough money

Are those shirts sold on eBay
I Googled it and searched on eBay for that, and I couldn't find it, but that doesn't mean it's not out there somewhere.

17. Originally Posted by Gelatino95
I was looking forward to getting a Stormrunner T-shirt at Hershey Park the other day, but I didn't have enough money

Are those shirts sold on eBay
http://store.hersheypa.com/hershey/a...arel-c103.aspx

It's red. Second from the bottom on the right

18. Half of the posts here aren't questions; what's up with that?

19. Bleh, both the Stormrunner and Fahrenheit shirts are ugly

I'll just wait till I go to the park again

20. Originally Posted by GonzalesTheySay
Half of the posts here aren't questions; what's up with that?
Is the Calus? or whatever he's called again?

21. Edit: nevermind this question. My brother was apparently lying to me that nothing happened when the system was moved- I guess it made a weird noise during movement. Unfortunately I already took the game back not knowing this and now I'll have to feel guilty about it.

I was playing a video game this afternoon. I started about 3 and at about 8:30 my brother came home with a new tv. The tv was HD, and the old one wasn't. I turned my game off and let him hook up the new tv. He then played a different video on the same system with his new tv. He didn't play for too long, and let me go back to mine. However, when I attempted to do this, the system would act like it was loading it, but then would say the disc is unreadable, despite the fact that it had only been removed from the system and set (shiny side up) on a nearby shelf.

Is there any reason this might've happened?I thought maybe changing from a regular tv to an HD might've changed something, but I doubt it. Also, is it possible the game could've been damaged if the system was on while the system was moved from being on its end to on its side?
Originally Posted by PikaPika677
If I had a standard deck of 52 playing card and shuffled it thoroughly, what are the chances of 2 cards of my choice (suits don't count. Only the value of the cards. Like 10 and 5 or Ace and King) appearing right next to each other when I look through the deck?
Of the answers given, I believe this one
Originally Posted by PsychedelicJellyfish
I think it's actually 1 in 13. Because when you look through the deck, you will always find one of the cards at some point, because it's in the deck, so the probability of finding the first card doesn't matter. The probability that's relevant is the likelihood of the other card you want being next to the first card. There's four cards of each value in the deck, so the likelihood of whatever card you want being next to the first card is 1 in 13.

For example, you look through the deck and find a king. The chance of an ace being next to it is 1 in 13.

I hope that makes sense. I have a nasty feeling that it doesn't.
is closest, but isn't totally complete. For the two cards to be next to each other, two subevents need to occur. The first is finding one of the two cards you selected, the second is finding the other choosen card directly after it.

The probability of the event is the probability of the subevents multiplied by each other.

The probability of finding one of the choosen cards (subevent 1) is 100%

The probabilty of finding one of the other chosen cards directly after (subevent 2) is:

(number of the other chosen cards remaining in the deck)/(number of cards remaining in the deck)

Since the probability of subevent 1 is 100%, the probabililty of the event is the same as that of subevent 2.

For example, let's say you choose 6 and K, and the first card you pull is a K. The probability that a 6 is next is 4/51, or about 7.8%. Let's then say that the next card was not a 6, so you continue. When you pull your 20th card, you find a 6. The probability of a K being next is 3(since you already removed one)/(52-20), or 9.375%
Last edited by PsychicPsycho; 26th May 2012 at 10:20 AM.

22. Originally Posted by Fading Echoes
If you delete your trade shop, are you allowed to make another one [for the same gen]?
Yes- as long as you stick by Trade Shops rules.

Question:
Is getting bleach in a cut bad?

23. Rain Trainer
Join Date
Nov 2011
Location
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Originally Posted by GonzalesTheySay
Half of the posts here aren't questions; what's up with that?
There are also answers.

Originally Posted by PsychicPsycho
Of the answers given, I believe this one
is closest, but isn't totally complete. For the two cards to be next to each other, two subevents need to occur. The first is finding one of the two cards you selected, the second is finding the other choosen card directly after it.

The probability of the event is the probability of the subevents multiplied by each other.

The probability of finding one of the choosen cards (subevent 1) is 100%

The probabilty of finding one of the other chosen cards directly after (subevent 2) is:

(number of the other chosen cards remaining in the deck)/(number of cards remaining in the deck)

Since the probability of subevent 1 is 100%, the probabililty of the event is the same as that of subevent 2.

For example, let's say you choose 6 and K, and the first card you pull is a K. The probability that a 6 is next is 4/51, or about 7.8%. Let's then say that the next card was not a 6, so you continue. When you pull your 20th card, you find a 6. The probability of a K being next is 3(since you already removed one)/(52-20), or 9.375%
Assume that you look through the deck from top to bottom. In a pair, I will refer to the one reached first as the first card and the other card in the pair as the second card.

The first thing to note is that there will be 7 firsts cards.

After each of these first cards, the probability of the card right after it being of the correct is 1/13. This does not change as you progress though the deck. This is because you will get cards of all values at a similar rate. In a specific example, it likely won't be at exactly the same rate, but the average of many tries will. Therefore, the chance of at least two card of those specific values being next to each other is 1-(12/13)^7.

24. What is the correct use of the word "legit" as a colloquial term

25. Originally Posted by Electricbluewolf
Yes- as long as you stick by Trade Shops rules.

Question:
Is getting bleach in a cut bad?
Not really

As soon as you get cut your blood coagulates, making a small barrier against outside influences. Of course, prolonged exposure to any sort of liquid on a wound will result in some of it being absorbed, but as long as it's not submerged in bleach for an an extended period of time, you should be fine

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